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Minimal Polynomials

An algebraic number is a complex number that satisfies some nonzero polynomial equation with rational coefficients. Thus $\alpha\in\mathbb{C}$ is algebraic if there exists a...

Algebraic Dependence Over Q\mathbb{Q}

An algebraic number is a complex number that satisfies some nonzero polynomial equation with rational coefficients. Thus αC\alpha\in\mathbb{C} is algebraic if there exists a nonzero polynomial

f(x)Q[x] f(x)\in\mathbb{Q}[x]

such that

f(α)=0. f(\alpha)=0.

Among all such polynomials, one is distinguished: the monic polynomial of least degree. This polynomial is called the minimal polynomial of α\alpha over Q\mathbb{Q}.

The minimal polynomial records the simplest exact algebraic relation satisfied by α\alpha.

Definition

Let α\alpha be algebraic over Q\mathbb{Q}. The minimal polynomial of α\alpha over Q\mathbb{Q} is the unique monic irreducible polynomial

mα(x)Q[x] m_\alpha(x)\in\mathbb{Q}[x]

such that

mα(α)=0. m_\alpha(\alpha)=0.

Here monic means that the leading coefficient is 11, and irreducible means that the polynomial cannot be factored nontrivially in Q[x]\mathbb{Q}[x].

For example, 2\sqrt2 satisfies

x22=0. x^2-2=0.

The polynomial x22x^2-2 is monic and irreducible over Q\mathbb{Q}, so it is the minimal polynomial of 2\sqrt2.

First Examples

The number ii satisfies

x2+1=0. x^2+1=0.

Since x2+1x^2+1 has no rational root, it is irreducible over Q\mathbb{Q}. Hence

mi(x)=x2+1. m_i(x)=x^2+1.

The number

1+52 \frac{1+\sqrt5}{2}

satisfies

x2x1=0. x^2-x-1=0.

This polynomial is monic and irreducible over Q\mathbb{Q}, so it is the minimal polynomial.

By contrast, the rational number 3/43/4 has minimal polynomial

x34. x-\frac34.

If one wants integer coefficients, one may write

4x3, 4x-3,

but the monic minimal polynomial over Q\mathbb{Q} is x3/4x-3/4.

Uniqueness

The minimal polynomial is unique.

Suppose f(x)f(x) and g(x)g(x) are both monic irreducible polynomials in Q[x]\mathbb{Q}[x] with

f(α)=0,g(α)=0. f(\alpha)=0, \qquad g(\alpha)=0.

Since ff is irreducible and g(α)=0g(\alpha)=0, the polynomial ff must divide gg. Similarly, gg must divide ff. Hence they have the same degree and differ only by a nonzero constant factor.

Because both are monic, that constant factor is 11. Therefore

f(x)=g(x). f(x)=g(x).

This proves uniqueness.

Divisibility Property

The minimal polynomial divides every polynomial that vanishes at α\alpha.

If

h(x)Q[x] h(x)\in\mathbb{Q}[x]

and

h(α)=0, h(\alpha)=0,

then

mα(x)h(x) m_\alpha(x)\mid h(x)

in Q[x]\mathbb{Q}[x].

This property makes the minimal polynomial the fundamental algebraic relation of α\alpha.

For example, 2\sqrt2 also satisfies

x44=0. x^4-4=0.

But

x44=(x22)(x2+2), x^4-4=(x^2-2)(x^2+2),

and its minimal polynomial x22x^2-2 appears as a factor.

Degree of an Algebraic Number

The degree of an algebraic number α\alpha is the degree of its minimal polynomial.

Thus

deg(2)=2,deg(i)=2,deg(1+52)=2. \deg(\sqrt2)=2, \qquad \deg(i)=2, \qquad \deg\left(\frac{1+\sqrt5}{2}\right)=2.

Every rational number has degree 11, since its minimal polynomial is linear.

The degree measures the algebraic complexity of the number over Q\mathbb{Q}. Larger degree means the number requires a higher-degree equation to describe it exactly.

Algebraic Integers and Minimal Polynomials

Minimal polynomials give a clean criterion for algebraic integers.

Theorem. An algebraic number α\alpha is an algebraic integer if and only if its minimal polynomial over Q\mathbb{Q} lies in

Z[x] \mathbb{Z}[x]

and is monic.

For example,

2 \sqrt2

is an algebraic integer because its minimal polynomial is

x22. x^2-2.

But

12 \frac12

is not an algebraic integer because its minimal polynomial is

x12, x-\frac12,

which does not have integer coefficients.

This criterion explains why algebraic integers generalize ordinary integers rather than rational numbers.

Conjugates

The roots of the minimal polynomial are called the conjugates of α\alpha.

For example, the minimal polynomial of 2\sqrt2 is

x22, x^2-2,

whose roots are

2and2. \sqrt2 \quad\text{and}\quad -\sqrt2.

Thus the conjugates of 2\sqrt2 are 2\sqrt2 and 2-\sqrt2.

For the golden ratio

φ=1+52, \varphi=\frac{1+\sqrt5}{2},

the conjugate is

152. \frac{1-\sqrt5}{2}.

Conjugates play a central role in defining norm, trace, discriminant, and embeddings of number fields.

Minimal Polynomials and Number Fields

If α\alpha is algebraic, then the field

Q(α) \mathbb{Q}(\alpha)

is generated by adjoining α\alpha to Q\mathbb{Q}. Its degree over Q\mathbb{Q} equals the degree of the minimal polynomial:

[Q(α):Q]=degmα. [\mathbb{Q}(\alpha):\mathbb{Q}] = \deg m_\alpha.

For example,

[Q(2):Q]=2. [\mathbb{Q}(\sqrt2):\mathbb{Q}]=2.

The field consists of all expressions

a+b2,a,bQ. a+b\sqrt2, \qquad a,b\in\mathbb{Q}.

Thus minimal polynomials connect individual algebraic numbers with the fields they generate.

Arithmetic Meaning

Minimal polynomials are not merely equations. They encode arithmetic data.

From the minimal polynomial, one can read:

the degree of the algebraic number,

the conjugates,

whether the number is an algebraic integer,

the field generated by the number,

and, in many cases, norm and trace.

For an algebraic integer, the minimal polynomial plays the role of an exact arithmetic fingerprint. It is the smallest polynomial identity that forces the number to exist.