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Galois Groups

A polynomial equation may possess several roots related by hidden algebraic symmetries. Consider

Symmetry of Polynomial Roots

A polynomial equation may possess several roots related by hidden algebraic symmetries. Consider

f(x)=x22. f(x)=x^2-2.

Its roots are

2and2. \sqrt{2} \qquad \text{and} \qquad -\sqrt{2}.

These roots can be exchanged without affecting any rational number. Indeed, the transformation

22 \sqrt{2}\mapsto -\sqrt{2}

preserves all algebraic relations involving rational coefficients. For example,

(2)2=2 (\sqrt{2})^2=2

remains true after the substitution.

Such transformations are called automorphisms of fields. The set of all automorphisms preserving the base field forms the Galois group.

The fundamental idea of Galois theory is that the arithmetic structure of a polynomial is encoded in the symmetries of its roots.

Field Automorphisms

Let LL be a field.

Definition. A field automorphism of LL is a bijection

σ:LL \sigma:L\to L

satisfying

σ(a+b)=σ(a)+σ(b) \sigma(a+b)=\sigma(a)+\sigma(b)

and

σ(ab)=σ(a)σ(b) \sigma(ab)=\sigma(a)\sigma(b)

for all a,bLa,b\in L.

Since multiplication is preserved, inverses are also preserved:

σ(a1)=σ(a)1 \sigma(a^{-1})=\sigma(a)^{-1}

whenever a0a\neq 0.

An automorphism therefore respects the entire field structure.

If KLK\subseteq L, we are usually interested in automorphisms that leave every element of KK fixed.

Definition. The Galois group of the extension L/KL/K is

Gal(L/K), \mathrm{Gal}(L/K),

the group of all field automorphisms of LL that fix KK pointwise.

Thus,

σ(a)=afor all aK. \sigma(a)=a \qquad \text{for all } a\in K.

Composition of maps gives the group operation.

First Example

Consider the extension

Q(2)/Q. \mathbb{Q}(\sqrt{2})/\mathbb{Q}.

Every element has the form

a+b2,a,bQ. a+b\sqrt{2}, \qquad a,b\in\mathbb{Q}.

An automorphism fixing Q\mathbb{Q} must send 2\sqrt{2} to another root of its minimal polynomial

x22. x^2-2.

The roots are

2and2. \sqrt{2} \qquad \text{and} \qquad -\sqrt{2}.

Therefore there are exactly two automorphisms:

  1. The identity automorphism
σ(a+b2)=a+b2. \sigma(a+b\sqrt{2})=a+b\sqrt{2}.
  1. The conjugation automorphism
τ(a+b2)=ab2. \tau(a+b\sqrt{2})=a-b\sqrt{2}.

Hence

Gal(Q(2)/Q) \mathrm{Gal}(\mathbb{Q}(\sqrt{2})/\mathbb{Q})

contains two elements.

As a group, it is isomorphic to the cyclic group

C2. C_2.

The extension degree is also 22:

[Q(2):Q]=2. [\mathbb{Q}(\sqrt{2}):\mathbb{Q}]=2.

This equality between extension degree and group size is a central feature of Galois extensions.

Automorphisms and Polynomial Roots

Let LL be the splitting field of a polynomial

f(x)K[x]. f(x)\in K[x].

Every automorphism in

Gal(L/K) \mathrm{Gal}(L/K)

permutes the roots of f(x)f(x).

Indeed, suppose α\alpha is a root:

f(α)=0. f(\alpha)=0.

Applying an automorphism σ\sigma, we obtain

σ(f(α))=σ(0)=0. \sigma(f(\alpha))=\sigma(0)=0.

Since σ\sigma fixes the coefficients of f(x)f(x),

f(σ(α))=0. f(\sigma(\alpha))=0.

Thus σ(α)\sigma(\alpha) is again a root of the polynomial.

Consequently, the Galois group acts as a permutation group on the roots.

This observation connects field theory with group theory.

Example: x32x^3-2

Consider

f(x)=x32 f(x)=x^3-2

over Q\mathbb{Q}. Its splitting field is

L=Q(23,ω), L=\mathbb{Q}(\sqrt[3]{2},\omega),

where ω\omega is a primitive cube root of unity.

The roots are

23,ω23,ω223. \sqrt[3]{2}, \qquad \omega\sqrt[3]{2}, \qquad \omega^2\sqrt[3]{2}.

Any automorphism fixing Q\mathbb{Q} must permute these roots.

One possible automorphism sends

23ω23 \sqrt[3]{2}\mapsto \omega\sqrt[3]{2}

while fixing ω\omega. Another sends

ωω2. \omega\mapsto \omega^2.

Together these generate a group of order 66, isomorphic to the symmetric group

S3. S_3.

Thus

Gal(L/Q)S3. \mathrm{Gal}(L/\mathbb{Q})\cong S_3.

The polynomial x32x^3-2 therefore possesses the full symmetry structure of permutations on three objects.

Fixed Fields

Given a subgroup

GGal(L/K), G\subseteq \mathrm{Gal}(L/K),

one may consider the elements fixed by every automorphism in GG.

Definition. The fixed field of GG is

LG={aL:σ(a)=a for all σG}. L^G= \{ a\in L:\sigma(a)=a \text{ for all } \sigma\in G \}.

For example, in

Q(2)/Q, \mathbb{Q}(\sqrt{2})/\mathbb{Q},

the nontrivial automorphism sends

a+b2ab2. a+b\sqrt{2}\mapsto a-b\sqrt{2}.

The only elements unchanged are those with b=0b=0. Hence the fixed field is precisely

Q. \mathbb{Q}.

The interaction between subgroups and fixed fields leads to the fundamental theorem of Galois theory.

Galois Extensions

Not every field extension behaves perfectly with respect to automorphisms. The best situation occurs when the extension is both normal and separable.

Definition. A finite extension L/KL/K is called a Galois extension if

  1. every irreducible polynomial in K[x]K[x] having one root in LL splits completely in LL;
  2. every irreducible polynomial has distinct roots.

For fields of characteristic zero, separability is automatic. Thus finite splitting fields over Q\mathbb{Q} are Galois extensions.

If L/KL/K is Galois, then

Gal(L/K)=[L:K]. |\mathrm{Gal}(L/K)|=[L:K].

This equality reveals that the algebraic size of the extension equals the number of its symmetries.

The Fundamental Theorem of Galois Theory

The central theorem of Galois theory establishes a correspondence between fields and groups.

Let L/KL/K be a finite Galois extension. Then:

  • every intermediate field
KEL K\subseteq E\subseteq L

corresponds to a subgroup

Gal(L/E); \mathrm{Gal}(L/E);
  • every subgroup
HGal(L/K) H\subseteq \mathrm{Gal}(L/K)

corresponds to a fixed field

LH. L^H.

These correspondences reverse inclusion:

E1E2Gal(L/E2)Gal(L/E1). E_1\subseteq E_2 \quad\Longleftrightarrow\quad \mathrm{Gal}(L/E_2)\subseteq \mathrm{Gal}(L/E_1).

Thus algebraic information about field extensions becomes equivalent to group-theoretic information about automorphisms.

This theorem is one of the deepest structural results in mathematics.

Solvability by Radicals

The historical origin of Galois theory was the study of polynomial equations.

Quadratic, cubic, and quartic equations admit formulas involving radicals. However, general quintic equations do not.

The reason lies in group theory.

A polynomial is solvable by radicals precisely when its Galois group is a solvable group.

For example:

  • quadratic equations correspond to groups of order 22;
  • general cubic equations correspond to subgroups of S3S_3;
  • general quintic equations correspond to S5S_5, which is not solvable.

Thus the impossibility of a general quintic formula is ultimately a theorem about symmetry.

Galois Groups in Number Theory

Galois groups govern much of modern number theory.

Cyclotomic fields, finite fields, elliptic curves, modular forms, and algebraic varieties all possess associated Galois actions. Arithmetic information is frequently encoded in how the absolute Galois group

Gal(Q/Q) \mathrm{Gal}(\overline{\mathbb{Q}}/\mathbb{Q})

acts on algebraic objects.

Modern theories such as class field theory and the Langlands program may be viewed as vast generalizations of the correspondence between arithmetic and symmetry first discovered by Évariste Galois.