IMO 1960
IMO 1960 — 7/7 solved, 6 verified.
IMO 1960
Official IMO 1960 problems · 7/7 solved, 6 verified.
| # | Status | Time |
|---|---|---|
| 1 | solved | 27m41s |
| 2 | ✓ verified | 7m41s |
| 3 | ✓ verified | 17m36s |
| 4 | ✓ verified | 33m08s |
| 5 | ✓ verified | 4m30s |
| 6 | ✓ verified | 3m00s |
| 7 | ✓ verified | 5m59s |
Problem 1 solved · 27m41s · Solution →
Find all three-digit numbers for which one obtains, when dividing the number by 11, the sum of the squares of the digits of the initial number.
Problem 2 ✓ verified · 7m41s · Solution →
For which real numbers $x$ does the following inequality hold: $$\frac{4x^2}{\left(1 - \sqrt{1+2x}\right)^2} < 2x + 9\,?$$
Problem 3 ✓ verified · 17m36s · Solution →
A right-angled triangle $ABC$ is given for which the hypotenuse $BC$ has length $a$ and is divided into $n$ equal segments ($n$ odd). Let $\alpha$ be the angle subtended at $A$ by the segment containing the midpoint of $BC$. If $h$ denotes the altitude from $A$, prove that $$\tan\alpha = \frac{4nh}{(n^2-1)a}.$$
Problem 4 ✓ verified · 33m08s · Solution →
Construct a triangle $ABC$ given the lengths of the altitudes $h_a$ and $h_b$ (from $A$ and $B$ respectively) and the length of the median $m_a$ from $A$.
Problem 5 ✓ verified · 4m30s · Solution →
Consider the cube $ABCDA'B'C'D'$ (with face $ABCD$ directly above face $A'B'C'D'$).
a) Find the locus of the midpoints of the segments $XY$, where $X$ is any point of $AC$ and $Y$ is any point of $B'D'$;
b) Find the locus of points $Z$ which lie on the segment $XY$ of part a) with $ZY = 2XZ$.
Problem 6 ✓ verified · 3m00s · Solution →
Consider a cone of revolution with an inscribed sphere tangent to the base of the cone. A cylinder is circumscribed about this sphere so that one of its bases lies in the base of the cone. Let $V_1$ be the volume of the cone and $V_2$ be the volume of the cylinder.
a) Prove that $V_1 \neq V_2$;
b) Find the smallest number $k$ for which $V_1 = kV_2$; for this case, construct the angle subtended by a diamter of the base of the cone at the vertex of the cone.
Problem 7 ✓ verified · 5m59s · Solution →
A regular cone is inscribed in a sphere. Around the sphere a cylinder is circumscribed so that its base lies in the same plane as the base of the cone. Let $V_1$ be the volume of the cone and $V_2$ that of the cylinder.
(a) Prove that $V_1 = V_2$ is impossible.
(b) Find the smallest $k$ for which $V_1 = k V_2$, and in this case construct the half-angle at the vertex of the cone.